Optimal. Leaf size=90 \[ \frac{1331 (3 x+2)^{m+1} \, _2F_1\left (1,m+1;m+2;\frac{2}{7} (3 x+2)\right )}{56 (m+1)}-\frac{5135 (3 x+2)^{m+1}}{216 (m+1)}-\frac{725 (3 x+2)^{m+2}}{108 (m+2)}-\frac{125 (3 x+2)^{m+3}}{54 (m+3)} \]
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Rubi [A] time = 0.0304623, antiderivative size = 90, normalized size of antiderivative = 1., number of steps used = 3, number of rules used = 2, integrand size = 22, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.091, Rules used = {88, 68} \[ \frac{1331 (3 x+2)^{m+1} \, _2F_1\left (1,m+1;m+2;\frac{2}{7} (3 x+2)\right )}{56 (m+1)}-\frac{5135 (3 x+2)^{m+1}}{216 (m+1)}-\frac{725 (3 x+2)^{m+2}}{108 (m+2)}-\frac{125 (3 x+2)^{m+3}}{54 (m+3)} \]
Antiderivative was successfully verified.
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Rule 88
Rule 68
Rubi steps
\begin{align*} \int \frac{(2+3 x)^m (3+5 x)^3}{1-2 x} \, dx &=\int \left (-\frac{5135}{72} (2+3 x)^m+\frac{1331 (2+3 x)^m}{8 (1-2 x)}-\frac{725}{36} (2+3 x)^{1+m}-\frac{125}{18} (2+3 x)^{2+m}\right ) \, dx\\ &=-\frac{5135 (2+3 x)^{1+m}}{216 (1+m)}-\frac{725 (2+3 x)^{2+m}}{108 (2+m)}-\frac{125 (2+3 x)^{3+m}}{54 (3+m)}+\frac{1331}{8} \int \frac{(2+3 x)^m}{1-2 x} \, dx\\ &=-\frac{5135 (2+3 x)^{1+m}}{216 (1+m)}-\frac{725 (2+3 x)^{2+m}}{108 (2+m)}-\frac{125 (2+3 x)^{3+m}}{54 (3+m)}+\frac{1331 (2+3 x)^{1+m} \, _2F_1\left (1,1+m;2+m;\frac{2}{7} (2+3 x)\right )}{56 (1+m)}\\ \end{align*}
Mathematica [A] time = 0.0492649, size = 71, normalized size = 0.79 \[ \frac{(3 x+2)^{m+1} \left (\frac{35937 \, _2F_1\left (1,m+1;m+2;\frac{2}{7} (3 x+2)\right )}{m+1}-\frac{3500 (3 x+2)^2}{m+3}-\frac{10150 (3 x+2)}{m+2}-\frac{35945}{m+1}\right )}{1512} \]
Antiderivative was successfully verified.
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Maple [F] time = 0.049, size = 0, normalized size = 0. \begin{align*} \int{\frac{ \left ( 3+5\,x \right ) ^{3} \left ( 2+3\,x \right ) ^{m}}{1-2\,x}}\, dx \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [F] time = 0., size = 0, normalized size = 0. \begin{align*} -\int \frac{{\left (3 \, x + 2\right )}^{m}{\left (5 \, x + 3\right )}^{3}}{2 \, x - 1}\,{d x} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [F] time = 0., size = 0, normalized size = 0. \begin{align*}{\rm integral}\left (-\frac{{\left (125 \, x^{3} + 225 \, x^{2} + 135 \, x + 27\right )}{\left (3 \, x + 2\right )}^{m}}{2 \, x - 1}, x\right ) \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F] time = 0., size = 0, normalized size = 0. \begin{align*} - \int \frac{27 \left (3 x + 2\right )^{m}}{2 x - 1}\, dx - \int \frac{135 x \left (3 x + 2\right )^{m}}{2 x - 1}\, dx - \int \frac{225 x^{2} \left (3 x + 2\right )^{m}}{2 x - 1}\, dx - \int \frac{125 x^{3} \left (3 x + 2\right )^{m}}{2 x - 1}\, dx \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int -\frac{{\left (3 \, x + 2\right )}^{m}{\left (5 \, x + 3\right )}^{3}}{2 \, x - 1}\,{d x} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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